Chapter 2697P26.61(a)CAd1102=∈κ; CAd22022=∈; CAd33022=∈1122310110123CCAdAd+FHGIKJ=+=∈+FHGIKJ=++FHGIKJ=∈++FHGIKJ−−κκFIG. P26.61(b)Using the given values we find:CtotalF pF=×=−176 1017612...*P26.62The initial charge on the larger capacitor isQCV===∆10150F15VCµµaf.An additional charge qis pushed through the 50-V battery, giving the smaller capacitor charge qandthe larger charge 150 Cµ+q.Then50515010VFCF+qq5002150117C CC+=qSo across the 5- Fcapacitor∆VqC=11723 3C5 FVAcross the 10- Fcapacitor∆V=+=15011726 7C10 FVP26.63(a)Put charge Qon the sphere of radius aand –Qon the other sphere. Relative to V=0 atinfinity,the potential at the surface of
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .