761_Physics ProblemsTechnical Physics

761_Physics ProblemsTechnical Physics - Chapter 26 P26.73...

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Chapter 26 101 P26.73 E max occurs at the inner conductor’s surface. E k a e max = 2 λ from Equation 24.7. Vk b a e = F H G I K J 2 ln from Example 26.2 E V ab a VE a b a max max max ln ln . . ln . . .. = = F H G I K J × F H G I K J = bg ej e j 18 0 10 0 800 10 300 0800 19 0 63 Vm m kV P26.74 E a = 2 κλ ; V b a = F H G I K J 2 ln a b a dV da E b a a ba b a max max max max ln ln = F H G I K J = F H G I K J + F H G I K J F H G I K J L N M M O Q P P = 1 0 2 ln b a F H G I K J = 1 or b a e = 1
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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