769_Physics ProblemsTechnical Physics

769_Physics ProblemsTechnical Physics - Chapter 27 5.00 A I...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 27 109 P27.8 (a) J I A == × = 500 99 5 3 2 . . A 4.00 10 m kA m 2 π ej (b) JJ 21 1 4 = ; I A I A 1 4 = AA 12 1 4 = so ππ 400 10 1 4 3 2 2 2 . ×= r r 2 33 2 4 00 10 8 00 10 8 00 = × = −− .. . m m m P27.9 (a) J I A × × = 800 10 100 10 255 6 3 2 . . . A m Am 2 (b) From Jn e v d = , we have n J ev d ×× 1 60 10 3 00 10 531 10 19 8 10 3 . . C m s m 2 e j . (c) From I Q t = , we have t Q I Ne I = × A C A s 6 02 10 1 60 10 120 10 23 19 6 10 . . e j . (This is about 382 years!) P27.10 (a) The speed of each deuteron is given by Km v = 1 2 2 2 00 10 1 60 10 1 2 2 1 67 10 61 9 2 7 2 . = × × e j e j J k g v and v 138 10 7 . m s . The time between deuterons passing a stationary point is t in I q t = 10 0 10 1 60 10 9 × Cs C t or t 160 10 14 s . So the distance between them is vt × = × 1 38 10 1 60 10
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online