771_Physics ProblemsTechnical Physics

# 771_Physics ProblemsTechnical Physics - 111 Chapter 27...

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Chapter 27 111 P27.16 J I r E == = = π σ 22 300 120 . A 0.012 0 m NC bg =⋅ 55 3 1 . m af ρ 1 00181 m P27.17 (a) Given MVA dd ρρ A where d mass density, we obtain: A M d = A . Taking r resistivity, R AM M rr d rd = AA A A 2 . Thus, A × ×× MR 100 10 0500 1 70 10 8 92 10 3 83 .. ej e j A = 182 m . (b) V M d = ,o r r M d 2 A = . Thus, r M d × × πρ A 892 10 182 3 3 . r 140 10 4 m . The diameter is twice this distance: diameter = 280 m µ . *P27.18 The volume of the gram of gold is given by = m V V m A A R A × = × ×⋅ × × 10 19 3 10 5 18 10 2 40 10 216 10 244 10 271 10 3 3 11 8 11 6 kg kg m m m m m 2.4 10 m m 3 3 2 3 2 . . . . . A P27.19 (a) Suppose the rubber is 10 cm long and 1 mm in diameter. R A
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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