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772_Physics ProblemsTechnical Physics

# 772_Physics ProblemsTechnical Physics - 112 P27.20 Current...

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112 Current and Resistance P27.20 The distance between opposite faces of the cube is A = F H G I K J = 90 0 2 05 1 3 . . g 10.5 g cm cm 3 . (a) R A = = = = × × = × = ρ ρ ρ A A A A 2 8 2 7 1 59 10 10 7 77 10 777 . . m 2.05 m n (b) I V R = = × × = 1 00 10 7 77 10 12 9 5 7 . . . V A n n = × = × × F H G I K J = × 10 5 107 87 6 02 10 5 86 10 1 00 10 1 00 5 86 10 23 22 6 28 . . . . . . . g cm g mol electrons mol electrons cm cm m m 3 3 3 3 3 e j e j I nqvA = and v I nqA = = × × = 12 9 5 86 10 1 60 10 0 020 5 3 28 28 19 2 . . . . . C s m C m m s 3 e je j b g µ P27.21 Originally, R A = ρ A . Finally, R A A R f = = = ρ ρ A A 3 3 9 9 b g . P27.22 ρ π ρ π Al Al Cu Cu A A r r b g b g 2 2 = r r Al Cu Al Cu = = × × = ρ ρ 2 82 10 1 70 10 1 29 8 8 . . . P27.23 J E = σ so σ = = × = × J E 6 00 10 100 6 00 10 13 15 1 . . A m V m m 2 a f P27.24 R A A d = + = + ρ ρ ρ ρ 1 1 1 2 2 2 1 1 2 2 2 A A A A R = × + × × = 4 00 10 0 250 6 00 10 0 400 3 00
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