772_Physics ProblemsTechnical Physics

772_Physics ProblemsTechnical Physics - 112 P27.20 Current...

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112 Current and Resistance P27.20 The distance between opposite faces of the cube is A = F H G I K J = 90 0 205 13 . . g 10.5 g cm cm 3 . (a) R A === = ×⋅ × = ρρρ AA A A 2 8 2 7 159 10 10 777 10 777 . . m 2.05 m n ΩΩ (b) I V R == × × = 100 10 12 9 5 7 . . . V A n n × F H G I K J 10 5 107 87 602 10 586 10 100 23 22 6 28 . . . . . . . gcm gmo l electrons mol electrons cm cm m m 3 3 3 3 3 ej In q v A = and v I nqA ×× = 12 9 5 86 10 1 60 10 0 020 5 328 28 19 2 . .. . . ±Cs m C m ms 3 e j bg µ P27.21 Originally, R A = ρ A . Finally, R R f = A A 3 399 . P27.22 π Al Al Cu Cu rr b g 22 = r r Al Cu Al Cu × × = 282 10 170 10 129 8 8 . . . P27.23 JE = σ so × J E 600 10 100 13 15 1 . . Am ±Vm m 2 af P27.24 R d =+= + ρρ 11 1 2 2 AAA A R = + × = −− 4 00 10 0 250 6 00 10 0 400 300 10 378 33 3 2 . m m m Section 27.3 A Model for Electrical Conduction
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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