776_Physics ProblemsTechnical Physics

776_Physics ProblemsTechnical Physics - 116 *P27.40 Current...

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116 Current and Resistance *P27.40 The battery takes in energy by electric transmission P ∆∆ tV I t == × F H G I K J = af a f ej 23 135 10 42 3600 469 3 .. . JC Cs h s 1 h J. It puts out energy by electric transmission VI t a f F H G I K J = 1 6 18 10 2 4 249 3 h s 1 h (a) efficiency = useful output total input J 469 J 249 0530 . (b) The only place for the missing energy to go is into internal energy: 469 249 221 J J J int int =+ = E E (c) We imagine toasting the battery over a fire with 221 J of heat input: Qm cT T Q mc = ° 221 15 1 Jk g C 0.015 kg 975 J C . P27.41 0 2 0 2 0 2 2 140 120 1361 F H G I K J = F H G I K J = VR V V a f bg . %. . = F H G I K J =− F H G
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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