116 Current and Resistance*P27.40The battery takes in energy by electric transmissionP∆∆∆tVIt==×FHGIKJ=−afafej23135 104236004693...JCCshs1 hJ.It puts out energy by electric transmissionVI taf=×FHGIKJ=−1 618 102 42493hs1 h(a)efficiency =useful outputtotal inputJ469 J2490530.(b)The only place for the missing energy to go is into internal energy:469249221J JJintint=+=∆∆EE(c)We imagine toasting the battery over a fire with 221 J of heat input:QmcTTQmc=°=°∆∆22115 1JkgC0.015 kg975 JC.P27.4102020221401201361FHGIKJ=FHGIKJ=∆∆∆∆VRVVafbg.∆%..=−FHGIKJ=−FHG
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .