Chapter 27121P27.56We find the drift velocity fromInqv Anqvrdd==π2vInq rvxttxvd××=×=××=−−−−−22831922434810008 49 101 60 1010234 10200 10108 54 1027.0 yrAm Cmmsm2.34m ss....ejejP27.57We begin with the differential equationαρ=1ddT.(a)Separating variables,ddTTT00zz=ln00FHGIKJ=−TTbgandρρ=−00e.(b)From the series expansion exx≅+1, x<<1af,−1.P27.58The resistance of one wire is 050010050 0..mimiΩΩFHGIKJ=af.The whole wire is at nominal 700 kV away from ground potential, but the potential differencebetween its two ends isIR500A kVafΩ.Then it radiates as heat power P×=∆VI50 0 101 00050 03V AMW.P27.59RAVIAAA∆A(m)( )(m)0.5401.0281.54310.421.131.8RΩΩ⋅×××−−−141 10
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Harshad number, Trigraph, Drift velocity, series expansion, eα bT