Chapter 27125P27.69Each speaker receives 60.0 W of power. Using P=I R2, we then haveIR===P60 03 87..W4.00 AΩ.The system is not adequately protectedsince the fuse should be set to melt at 3.87 A, or less.P27.70∆VE= −⋅Aor dVE dx= −⋅∆VIREIdqdtERAEAEAdVdxAdVdx= −= −⋅==⋅=⋅== −=AAAAρρσσCurrent flows in the direction of decreasing voltage. Energy flows as heat in the direction ofdecreasing temperature.P27.71RdxAdxwy==zzρρwhere yyyyLx=+−121RwdxyyyL xLw yyyyyLxRLw yyyyLL=+−=−+−LNMOQP=−FHGIKJzρρρ12102112102121bgbgbglnlnFIG. P27.71P27.72From the geometry of the longitudinal section of the resistor shown in the figure,we see thatbrybah−=−af af.From this, the radius at a distance yfrom the base israbyhb=−+af.For a disk-shaped element of volume
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