796_Physics ProblemsTechnical Physics

796_Physics ProblemsTechnical Physics - 136 P28.11 Direct...

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136 Direct Current Circuits P28.11 (a) Since all the current in the circuit must pass through the series 100 resistor, P = IR 2 max max = RI 2 so I R max . . == = 25 0 0500 W 100 A R VR I eq eq =+ + F H G I K J = 100 1 100 1 100 150 75 0 1 V ΩΩ max max . (b) = IV 750 375 .. . A V W af a f total power PP 1 23 2 2 25 0 100 0 250 6 25 = = . W W RI a f FIG. P28.11 P28.12 Using 2.00- , 3.00- , 4.00- resistors, there are 7 series, 4 parallel, and 6 mixed combinations: Series 2.00 6.00 3.00 7.00 4.00 9.00 5.00 Parallel Mixed 0.923 1.56 1.20 2.00 1.33 2.22 1.71 3.71 4.33 5.20 The resistors may be arranged in patterns: P28.13 The potential difference is the same across either combination. VI R I R + 3 1 11 500 ch so R R 500 3 + F H G I K J = 1 500 3 += R and R 1000 100 k FIG. P28.13 *P28.14 When S is open , R 1 , R 2 , R 3 are in series with the battery. Thus:
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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