797_Physics ProblemsTechnical Physics

# 797_Physics ProblemsTechnical Physics - Chapter 28 P28.15...

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Chapter 28 137 P28.15 R R I V R p s s =+ F H G I K J = =++ = == = 1 300 1 100 0750 2 00 0 750 4 00 6 75 18 0 267 1 .. . . . . . V 6.75 A battery ΩΩ a f P = IR 2 : 2 2 200 = A a f a f 2 14 2 = . W in 2.00 4 2 2 4 24 31 3 3 2 3 2 1 1 1 2 2 67 4 00 28 4 533 2 67 4 00 10 67 18 0 2 00 133 400 = −−= = = . . . . . . . . . A A W in 4.00 V , V V V V W in 3.00 V W in 1.00 af bg bga f a f ∆Ω ∆∆ V V VV V V V V R V R p FIG. P28.15 P28.16 Denoting the two resistors as x and y , xy += 690, and 1 150 11 1 150 690 690 690 690 103 500 0 690 690 414 000 2 470 220 2 2 = −+ = = ±− xx x a f *P28.17 A certain quantity of energy E int time = is required to raise the temperature of the water to 100 ° C. For the power delivered to the heaters we have IV V R a f 2 where V is a constant. Thus comparing coils 1 and 2, we have for the energy Vt
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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