800_Physics ProblemsTechnical Physics

800_Physics ProblemsTechnical Physics - 140 P28.22 Direct...

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140 Direct Current Circuits P28.22 The solution figure is shown to the right. FIG. P28.22 P28.23 We use the results of Problem 28.21. (a) By the 4.00-V battery: ∆∆ UV I t == = a f a fa f 4 00 0 462 120 222 .. V A s J . By the 12.0-V battery: 12 0 1 31 120 1 88 . A s k J af = . (b) By the 8.00- resistor: IRt 2 2 0846 800 120 687 ∆Ω A J a f a f . By the 5.00- resistor: 0 462 5 00 120 128 2 J a f a f Ω= . By the 1.00- resistor: 0 462 1 00 120 25 6 2 . s J a f a f . By the 3.00- resistor: 1 31 3 00 120 616 2 J a f . By the 1.00- resistor: 1 31 1 00 120 205 2 J . (c) −+ = 222 1 88 1 66 J kJ kJ . . from chemical to electrical. 687 128 25 6 616 205 1 66 J J J k J ++ ++= . . from electrical to internal. P28.24 We name the currents I 1 , I 2 , and I 3 as shown.
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