140 Direct Current CircuitsP28.22The solution figure is shown to the right.FIG. P28.22P28.23We use the results of Problem 28.21.(a)By the 4.00-V battery:∆∆∆UV I t==−=−afafaf4 000 462120222..VAsJ .By the 12.0-V battery:12 01 311201 88...VAskJafaf=.(b)By the 8.00-Ωresistor:I R t220 8468 00120687∆Ω==..AsJaf af.By the 5.00-Ωresistor:0 4625 001201282..AsJaf afΩ=.By the 1.00-Ωresistor:0 4621 0012025 62...AsJaf afΩ=.By the 3.00-Ωresistor:1 313 001206162..AsJaf afΩ=.By the 1.00-Ωresistor:1 311 001202052..AsJaf afΩ=.(c)−+=2221 881 66JkJkJ..from chemical to electrical.68712825 66162051 66JJJJJkJ++++=..from electrical to internal.P28.24We name the currents
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