801_Physics ProblemsTechnical Physics

801_Physics ProblemsTechnical Physics - Chapter 28 P28.25...

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Chapter 28 141 P28.25 Label the currents in the branches as shown in the first figure. Reduce the circuit by combining the two parallel resistors as shown in the second figure. Apply Kirchhoff’s loop rule to both loops in Figure (b) to obtain: 2 71 1 71 250 12 .. RI af += and 1 71 3 71 500 . With R = 1000 , simultaneous solution of these equations yields: I 1 10 0 = . mA and I 2 130 0 = . From Figure (b), VV I I R ca −=+ = 171 240 bg . V . Thus, from Figure (a), I VV R 4 4 240 60 0 = == V 4 000 mA Finally, applying Kirchhoff’s point rule at point a in Figure (a) gives: II I =−= = + 41 60 0 10 0 50 0 . mA mA mA, or Ia e = 50 0 . mA from point to point . (a) (b) FIG. P28.25 P28.26 Name the currents as shown in the figure to the right. Then wxzy ++= . Loop equations are −− + = −+ + = +− + = 200 40 0 80 0 0 80 0 40 0 360
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