803_Physics ProblemsTechnical Physics

803_Physics ProblemsTechnical Physics - Chapter 28 P28.30...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 28 143 P28.30 We apply Kirchhoff’s rules to the second diagram. 50 0 2 00 2 00 0 12 .. . −−= II (1) 20 0 2 00 2 00 0 32 . −+= (2) III 123 =+ (3) Substitute (3) into (1), and solve for I 1 , I 2 , and I 3 I 1 20 0 = . A ; I 2 500 = . A ; I 3 15 0 = . Then apply P = IR 2 to each resistor: 200 1 af : == = I 1 2 2 800 . A W ΩΩ a f a f a f 400 : = F H G I K J = 2 250 2 . W (Half of I 2 goes through each) 3 : = I 3 2 2 150 450 . W a f a f a f . FIG. P28.30 Section 28.4 RC Circuits P28.31 (a) RC × = 1 00 10 5 00 10 5 00 66 . F s ej e j (b) QC × = εµ 500 10 300 6 C V C (c) It R e tRC e j × F H G I K J ×× L N M M O Q P P = ε µ 30 0 10 0 1 00 10 5 00 10 406 . exp . . 1.00 10 A 6 FIG. P28.31 P28.32 (a) Ie a f =− 0 I Q RC 0 6 9 6 9 510 10 200 10 196 900 10 61 6 × × = −× × L N M M O Q P P . . . .e x p . . . C 1300 F A A s F mA bg a f (b) qt Qe a f × L N M M O Q P P = 510 800 10 0235 6 9 x p . . . C s 1 300
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online