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803_Physics ProblemsTechnical Physics

# 803_Physics ProblemsTechnical Physics - Chapter 28 P28.30...

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Chapter 28 143 P28.30 We apply Kirchhoff’s rules to the second diagram. 50 0 2 00 2 00 0 1 2 . . . = I I (1) 20 0 2 00 2 00 0 3 2 . . . + = I I (2) I I I 1 2 3 = + (3) Substitute (3) into (1), and solve for I 1 , I 2 , and I 3 I 1 20 0 = . A ; I 2 5 00 = . A ; I 3 15 0 = . A. Then apply P = I R 2 to each resistor: 2 00 1 . a f : P = = = I 1 2 2 2 00 20 0 2 00 800 . . . A W a f a f a f 4 00 . a f : P = F H G I K J = 5 00 2 4 00 25 0 2 . . . A W a f (Half of I 2 goes through each) 2 00 3 . a f : P = = = I 3 2 2 2 00 15 0 2 00 450 . . . A W a f a f a f . FIG. P28.30 Section 28.4 RC Circuits P28.31 (a) RC = × × = 1 00 10 5 00 10 5 00 6 6 . . . F s e je j (b) Q C = = × = ε µ 5 00 10 30 0 150 6 . . C V C e j a f (c) I t R e t RC a f e je j = = × F H G I K J × × L N M M O Q P P = ε µ 30 0 10 0 1 00 10 5 00 10 4 06 6 6 . exp . . . . 1.00 10 A 6 FIG. P28.31 P28.32 (a) I t I e t RC a f = − 0 I Q RC I t 0 6 9 6 9 5 10 10 2 00 10 1 96 1 96 9 00 10 2 00 10 61 6 = = × × = = − × × L N M M O Q P P = . . . . exp
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