807_Physics ProblemsTechnical Physics

# 807_Physics ProblemsTechnical Physics - Chapter 28 P28.45...

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Chapter 28 147 P28.45 Consider the circuit diagram shown, realizing that I g = 100 . mA . For the 25.0 mA scale: 24 0 1 00 25 0 123 .. . mA mA af bg a f RRR ++ = FIG. P28.45 or 25 0 24 0 ++= F H G I K J . . . (1) For the 50.0 mA scale: 49 0 1 00 25 0 12 3 . mA mA RR R += + or 49 0 25 0 3 R + . (2) For the 100 mA scale: 99 0 1 00 25 0 3 . mA mA R =+ + or 99 0 25 0 3 R + . (3) Solving (1), (2), and (3) simultaneously yields 0 260 0 261 0 521 === ... , ΩΩΩ . P28.46 VI R = (a) 20 0 1 00 10 60 0 3 1 . V A + ej R R 1 4 1 994 10 19 94 = k ΩΩ FIG. P28.46 (b) 50 0 1 00 10 60 0 3 21 . A + + R 2 30 0 = . k (c) 100 1 00 10 60 0 3 31 A + + R 3 50 0 = P28.47 Ammeter: I r I gg =− 0 500 0 220 A or Ir g 0 220 0 110 V (1) Voltmeter: 200 2500 . V g (2) Solve (1) and (2) simultaneously to find:
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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