150 Direct Current Circuits(b)The hot pot is designed to carrycurrentIV===P∆500417W120 VA..It has resistanceRVI=∆Ω12028 8V4.17 A28.8Ω240 V144ΩFIG. P28.56(b)In terms of current, since 5. A0.833 A=, we can place five light bulbs in parallel and the hotpot in series with their combination. The current in the generator is then A and itdelivers power =IV∆4 172401 000A VWaf.P28.57The current in the simple loop circuit will be IRr=+ε.(a)∆VIrRter=− =+and∆Vter→as R→∞.(b)I=+andIr→as R→0.(c)+IRR222ddRR=−+++=202322εεThen 2RRr=+and=.FIG. P28.57P28.58The potential difference across the capacitor
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