Chapter 28151P28.59Let the two resistances be xand y.Then,RxyIss=+= ==P22225900W5.00 Aaf.Ωyx=−. ΩandRxyxyIpp=+===50 0200..W5.00 AafΩsoxx...ΩΩΩ−+−=af2180 0−+=...Factoring the second equation,−−=6003000sox=Ωor x=Ω.Then, Ωgivesy=Ωor y=Ω.The two resistances are found to be Ωand Ω.xyxyFIG. P28.59P28.60Let the two resistances be xand y.Then, Iss=+=2and RxyIpp=+=2.From the first equation, yIxs2, and the secondbecomes xIxxIxIssp222−=ejor xIxIssp2240−FHGIKJ+=PP.Using the quadratic formula, xIsssp=±−2242.Then, yIxs2gives yIsp=−∓2242.The two resistances are spI2242and spI2242.xyxyFIG. P28.60P28.61(a)εεε+=∑IRchbg12040 04 002 00 0 300 0 3006 00 6 000.....V AV−+++−+=afafRΩ;soR=440Ω(b)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .