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813_Physics ProblemsTechnical Physics

# 813_Physics ProblemsTechnical Physics - Chapter 28 FG H IJ...

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Chapter 28 153 P28.64 The battery supplies energy at a changing rate dE dt I R e RC === F H G I K J P εε ε 1 . Then the total energy put out by the battery is dE R t RC dt t zz =− F H G I K J = 2 0 exp dE R RC t RC dt RC C t RC CC F H G I K J F H G I K J F H G I K J = 2 0 2 0 22 01 af exp exp . The power delivered to the resistor is dE dt VI IR R R t RC R == = = F H G I K J 2 2 2 2 exp . So the total internal energy appearing in the resistor is dE R t RC dt F H G I K J 2 0 2 exp dE R RC t RC dt RC Ct RC F H G I K J F H G I K J F H G I K J F H G I K J − = 2 0 2 0 2 2 2 2 2 exp exp . The energy finally stored in the capacitor is UC V C 1 2 1 2 2 2 . Thus, energy of the circuit is conserved εεε 222 1 2 1 2 CCC =+ and resistor and capacitor share equally in the energy from the battery. P28.65 (a) qCV e tRC 1 ej qe L N M O Q P = −× × 100 10 100 1 993 6 10 0 2 00 10 1.00 10 66 .. . F V C a f e j µ (b) I
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