816_Physics ProblemsTechnical Physics

816_Physics ProblemsTechnical Physics - 156*P28.70 Direct...

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156 Direct Current Circuits *P28.70 From the hint, the equivalent resistance of . That is, R RR R T Le q eq + + = 1 11 R R R R R R R T q q eq TL Te q q q e q eq T eq T L eq TT T L + + = ++=+ −−= = ±−− 2 2 2 0 41 21 af bg Only the + sign is physical: R R R eq T L T T =+ + F H I K 1 2 4 2 . For example, if R T = 1 . And R L = 20 , R eq = 5 . P28.71 (a) After steady-state conditions have been reached, there is no DC current through the capacitor. Thus, for R 3 : I R 3 0 = steady-state . For the other two resistors, the steady-state current is simply determined by the 9.00-V emf across the 12-k and 15-k resistors in series: For R 1 and R 2 : I 12 900 15 0 333 + = + = + = a f ε µ . .
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