158 Direct Current CircuitsP28.73∆VetRC=−εsoln∆VRCtFHGIKJ=FHGIKJ1.A plot of ln∆VFHGIKJversus tshouldbe a straight line with slope equalto 1RC.Using the given data values:FIG. P28.73(a)A least-square fit to this data yields the graph above.xi∑=282,xi24186 10∑=×.,xyii∑=244,yi∑=403N=8Slope =−−=∑∑∑Nxyxyxiichchej2200118.Intercept =−−=∑∑xxyxiii22200882ch.tsVVVa fafbg∆∆ln04.8711.119.430.846.667.318.104.22.1684.934.343.723.092.471.8300.1090.2280.3550.5090.6950.9191.219The equation of the best fit line is:ln..∆VtFHGIKJ=+.(b)Thus, the time constant isτ====RC1184 7slopes..and the capacitance isCR×=µ84 710 0 108476...sFΩ.P28.74(a)For the first measurement, the equivalent circuit is asshown in Figure 1.R RRR Rabyyy==+=1
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .