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820_Physics ProblemsTechnical Physics

# 820_Physics ProblemsTechnical Physics - 160 Direct Current...

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160 Direct Current Circuits ANSWERS TO EVEN PROBLEMS P28.2 (a) 1 79 . A; (b) 10 4 . V P28.42 0 113 . P28.44 (a) 30 000 . mA , 5 400 0 . V ; P28.4 (a) 12 4 . V ; (b) 9 65 . V (b) 30 167 . mA, 5 381 6 . V ; P28.6 (a) 17 1 . ; (b) 1 99 . A in 4 and 9 ; 1 17 . A in 7 ; 0 818 . A in 10 (c) 29 898 . mA ; 5 396 6 . V P28.46 see the solution P28.8 29 5 . V P28.48 (a) 0.101 W; (b) 10.1 W P28.10 (a) see the solution; (b) no P28.50 15.5 A P28.12 see the solution P28.52 2 22 . h P28.14 R 1 1 00 = . k ; R 2 2 00 = . k ; R 3 3 00 = . k P28.54 a is 4 00 . V higher P28.16 470 and 220 P28.56 (a) see the solution; 833 mA; 200 W; P28.18 (a) 11 0 . ; (b) and (d) see the solution; (b) see the solution; 4.17 A; 1.00 kW (c) 220 ; (e) Parallel P28.58 587 k P28.20 I 1 714 = mA ; I 2 1 29 = . A ; ε = 12 6 . V P28.60 P P P P s s s p I + 2 2 4 2 and P P P P s s s p I 2 2 4 2 P28.22 see the solution P28.24 (a) 0 385 . mA in R 1 ; 2 69 . mA in R 3 ; 3 08 . mA in R 2 ; (b) c higher by 69 2 . V P28.62 (a) I IR R R 1 2 1 2 = + b g ; I IR R R 2 1 1 2 = + ; (b) see the solution
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