166 Magnetic FieldsP29.14FBBmgIImgBAAAAA==×=004009803600109....kg mm sTA2bgejThe direction of Iin the bar is to the right .BinFFIG. P29.14P29.15The rod feels force FdBkjiBIIdBIdB=×=×−=afe j±±±.The work-energy theorem is KKEiftrasnrottransrot++=+∆00121222=+FmvIscosθωIdBLmvmRvRcos01212122°=+FHGIKJFHGIKJand IdBLmv=342vIdBLm=434 48 00 1200 2400 45030720107....A m T mkgmsafafaf.dILByxzFIG. P29.15P29.16The rod feels force BkjiBdBIdB=×−=±.The work-energy theorem is Etransrottransrot=+∆1212=+FsmvIcosIdBLmvmRvR1212122+FHGIKJFHGIKJand vIdBLm=43.P29.17The magnetic force on each bit of ring is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .