826_Physics ProblemsTechnical Physics

# 826_Physics ProblemsTechnical Physics - 166 P29.14 Magnetic...

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166 Magnetic Fields P29.14 F B B mg I I mg B AA A A A == × = 00400 980 360 0109 .. . . kg m m s T A 2 bg ej The direction of I in the bar is to the right . B in F FIG. P29.14 P29.15 The rod feels force Fd B k j i B II d B I d B = × = af e j ±± ± . The work-energy theorem is KK E if trasn rot trans rot ++ = + 00 1 2 1 2 22 = + Fm v I s cos θω IdBL mv mR v R cos0 1 2 1 2 1 2 2 °= + F H G I K J F H G I K J and IdBL mv = 3 4 2 v IdBL m = 4 3 4 48 0 0 120 0 240 0 450 30720 107 . . . . A m T m kg ms a f a f a f . d I L B y x z FIG. P29.15 P29.16 The rod feels force B k j i B d B I d B = × = ± . The work-energy theorem is E trans rot trans rot = + 1 2 1 2 = + Fs mv I cos IdBL mv mR v R 1 2 1 2 1 2 2 + F H G I K J F H G I K J and v IdBL m = 4 3 . P29.17 The magnetic force on each bit of ring is
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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