827_Physics ProblemsTechnical Physics

827_Physics ProblemsTechnical Physics - Chapter 29 P29.18...

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Chapter 29 167 P29.18 For each segment, I = 500 . A and Bj =⋅ 00200 . ± NAm. Segment . m 0.400 m mN . m . m mN . m . m mN AA FB j ki ij k ik k i B I ab bc cd da −+ af ej 0400 0 40 0 0 400 0 400 40 0 0 400 0 400 40 0 ± ± . ± ±± . ± . FIG. P29.18 P29.19 Take the x -axis east, the y -axis up, and the z -axis south. The field is Bk j 52 0 60 0 52 0 60 0 .c o s . ± .s i n . ± T T µµ bg . The current then has equivalent length: =− + Lkj 140 0850 . ± . ± m m e j FL B j k j k Fi i i B B I =′ ×= × −− = 0 035 0 0 850 1 40 45 0 26 0 10 3 50 10 22 1 63 0 2 98 10 2 98 6 86 .. ± . ± . ± . ± ± . ± . ± . A m T N N N w e s t e j e j µ . FIG. P29.19 Section 29.3 Torque on a Current Loop in a Uniform Magnetic Field
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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