828_Physics ProblemsTechnical Physics

828_Physics ProblemsTechnical Physics - 168 P29.22 Magnetic...

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168 Magnetic Fields P29.22 (a) Let θ represent the unknown angle; L , the total length of the wire; and d , the length of one side of the square coil. Then, using the definition of magnetic moment and the right-hand rule in Figure 29.15, we find µ = NAI : = F H G I K J L d dI 4 2 at angle with the horizontal. At equilibrium, τ =×−× = Br g bg b g m 0 ILBd mgd 4 90 0 2 0 F H G I K J °− F H G I K J = sin . sin θθ af and mgd ILBd 24 F H G I K J = F H G I K J sin cos = F H G I K J = F H G G I K J J −− tan tan ... .. . 11 2 340 400 00100 2 0 100 9 80 397 ILB mg A m T kg m s 2 ej . (b) τθ m ILBd = F H G I K J = 4 1 4 3 40 4 00 0 010 0 0 100 3 97 3 39 c o s... . c o s m T m m N m P29.23 τφ = ° =⋅ NBAI sin . . s i n . 100 0 800 0 400 0 300 1 20 60 998 T m A Nm 2 a f a f Note that φ is the angle between the magnetic moment and the B field. The loop will rotate so as to align the magnetic moment with the B field. Looking down along the y -axis, the loop will rotate in a clockwise direction. FIG. P29.23 P29.24 From =×= × BAB I , the magnitude of the torque is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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