835_Physics ProblemsTechnical Physics

835_Physics ProblemsTechnical Physics - Chapter 29 P29.47 =...

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Chapter 29 175 P29.47 θ = F H G I K J tan . . . 1 25 0 10 0 68 2 and R = ° = 100 68 2 108 . sin . . cm cm. Ignoring relativistic correction, the kinetic energy of the electrons is 1 2 2 mv q V =∆ so v qV m == × 2 133 10 8 . m s . From Newton’s second law mv R qvB 2 = , we find the magnetic field B mv qR ×× = −− 9 11 10 1 33 10 1 60 10 1 08 10 70 1 31 8 19 2 .. . kg m s C m mT ej e j . FIG. P29.47 Section 29.6 The Hall Effect P29.48 (a) R nq H 1 so n qR 11 1 6 01 0 0 8 4 0 744 10 19 10 28 3 H 3 m C m . e j (b) V IB nqt H = B nqt V I ××× × = H m C m V A T bg e j e j e j 7 44 10 1 60 10 0 200 10 15 0 10 20 0 179 28 3 19 3 6 . . P29.49 Since V IB nqt H = , and given that I = 50 0 . A , B = 130 . T, and t = 0330 . mm, the number of charge
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