836_Physics ProblemsTechnical Physics

836_Physics ProblemsTechnical Physics - 176 P29.50 Magnetic...

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176 Magnetic Fields P29.50 (a) V IB nqt H = so nqt I B V == × H T 0.700 V TV 00800 10 114 10 6 5 . .. Then, the unknown field is B nqt I V = F H G I K J H bg B × = = 1 14 10 0 330 10 0 037 7 37 7 56 . . V T mT ej . (b) nqt I 5 . T V s o n I qt 5 T V n ×× −− 0120 10 2 00 10 429 10 5 19 3 25 3 . . . . A 1.60 C m m . P29.51 B nqt V I × × H m C m V A e j e j e j 8 49 10 1 60 10 5 00 10 5 10 10 800 28 3 19 3 12 . . . B = 433 10 433 5 T T µ Additional Problems P29.52 (a) The boundary between a region of strong magnetic field and a region of zero field cannot be perfectly sharp, but we ignore the thickness of the transition zone. In the field the electron moves on an arc of a circle: Fm a = : qvB mv r v r qB m sin . . . 90 160 10 10 911 10 176 10 2 19 3 31 8 °= == = ×⋅ × ω C N s C m kg rad s e j FIG. P29.52(a) The time for one half revolution is,
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