850_Physics ProblemsTechnical Physics

# 850_Physics ProblemsTechnical Physics - 190 P30.8 Sources...

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190 Sources of the Magnetic Field P30.8 Along the axis of a circular loop of radius R , B IR x R = + µ 0 2 2 2 3 2 2 e j or B B x R 0 2 3 2 1 1 = + L N M M O Q P P b g where B I R 0 0 2 µ . FIG. P30.8 x R B B 0 0.00 1.00 1.00 0.354 2.00 0.0894 3.00 0.0316 4.00 0.0143 5.00 0.00754 *P30.9 Wire 1 creates at the origin magnetic field B 1 0 2 = µ π I r right hand rule = µ π 0 1 2 I a = µ π 0 1 2 I a ± j (a) If the total field at the origin is 2 2 2 0 1 0 1 2 µ π µ π I a I a ± ± j j B = + then the second wire must create field according to B j 2 0 1 0 2 2 2 2 = = µ π µ π I a I a ± a f . Then I I I 2 1 1 2 2 = = out of the paper ± k . (b) The other possibility is B B j j B 1 2 0 1 0 1 2 2 2 2 + = = + µ π µ π I a I a ± ± e j . Then B j 2 0 1 0 2 3 2 2 2 = = µ π µ π I a I a ± e j a f I I I 2 1 1 6 6 = = into the paper ± k e j *P30.10 Every element of current creates magnetic field in the same direction, into the page, at the center of the arc. The upper straight portion creates one-half of the field that an infinitely long straight wire
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