Chapter 30193P30.15Take the x-direction to the right and the y-direction up in the plane of thepaper. Current 1 creates at P a fieldBIa1072200 1030000500==×⋅−µπ...TmAA mejafbgB112 0=. Tdownward and leftward, at angle 67.4°below the –xaxis.Current 2 contributesB270120=−.Amafclockwise perpendicular to 12.0 cmB2500=to the right and down, at angle –22.6°5.00 cm13.0 cm12.0 cmPI1I2B2B1FIG. P30.15Then,BB Bijij=+=−°−° +°−°1212 067 467 45 0022 622 6.±cos.±sin..±cos.±sin.T TµµBjjj=−−= −1111 9213 0.±.±.±TTbgSection 30.2The Magnetic Force Between Two Parallel ConductorsP30.16Let both wires carry current in the xdirection, the first at y=0 and thesecond at y=10 0. cm.(a)Bkk−07241050020100Ir±..±TmAAmB=×−100 105.T out of the pageyy= 10.0 cmI1= 5.00 AI2= 8.00 AzxFIG. P30.16(a)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .