855_Physics ProblemsTechnical Physics

# 855_Physics ProblemsTechnical Physics - Chapter 30 P30.20...

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Chapter 30 195 P30.20 The separation between the wires is a = 2 6 00 8 00 1 67 .s i n . . cm cm af . (a) Because the wires repel, the currents are in opposite directions . (b) Because the magnetic force acts horizontally, F F I amg B g == ° µ π 0 2 2 800 A tan . I mg a 2 0 2 A tan . so I = 67 8 . A. FIG. P30.20 Section 30.3 Ampère’s Law P30.21 Each wire is distant from P by 0 200 45 0 0 141 .c o s . . m m a f °= . Each wire produces a field at P of equal magnitude: B I a A ×⋅ = 0 7 2 200 10 500 0141 707 .. . . TmA A m T ej a f . Carrying currents into the page, A produces at P a field of . T to the left and down at –135°, while B creates a field to the right and down at – 45°. Carrying currents toward you, C produces a field downward and to the right at – 45°, while D ’s contribution is downward and to the left. The
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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