Chapter 30203*P30.52At a point at distance xfrom the left end of the bar, currentI2creates magnetic field B=+µπ02222Ihxto the left andabove the horizontal at angle θwhere tan=xh. This fieldexerts force on an element of the rod of length dxdIIIdxIIdxxFB=×=+=++1101222Asinright hand ruleinto the pagedIIxdxFk=+−2ej±BI1xI2hFIG. P30.52The whole force is the sum of the forces on all of the elements of the bar:kk=+−=−+=−+=−+−=−+LNMMOQPP−=×−=−−−zz00027223224244102000510210401 12010IIxdxhhxafafafafaf±±±ln±lnln±ln..±ln.±AAAAN100AAAcmcmcmN NP30.53On the axis of a current loop, the magnetic field is given byBIRxR=+022where in this case Iq=2πωbg. The magnetic field is directed away from the center, with a magnitudeofBRq=+=×+−−µω0202622
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .