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887_Physics ProblemsTechnical Physics

# 887_Physics ProblemsTechnical Physics - 227 Chapter 31...

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Chapter 31 227 P31.40 (a) ε ω π ω max = = F H G I K J BA B R 1 2 2 ε π π ε max max . . . . = = 1 30 2 0 250 4 00 1 60 2 T m rad s V a f a f b g (b) ε ε π θ ω π θ θ π π = = = z z 2 2 0 0 2 0 2 d BA d sin (c) The maximum and average ε would remain unchanged. (d) See Figure 1 at the right. (e) See Figure 2 at the right. Figure 2 ε ε Figure 1 t t FIG. P31.40 P31.41 (a) Φ B BA BA t t t = = = = cos cos . . cos . . cos θ ω π 0 800 0 010 0 2 60 0 8 00 377 T m mT m 2 2 a f e j a f e j a f (b) ε = − = d dt t B Φ 3 02 377 . sin V a f a f (c) I R t = = ε 3 02 377 . sin A a f a f (d) P = = I R t 2 2 9 10 377 . sin W a f a f (e) P = = Fv τω so τ ω = = P 24 1 377 2 . sin mN m a f a f t Section 31.6 Eddy Currents P31.42 The current in the magnet creates an upward magnetic field, so the N and S poles on the solenoid core are shown correctly. On the rail in front of the brake, the upward flux of
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