887_Physics ProblemsTechnical Physics

887_Physics ProblemsTechnical Physics - 227 Chapter 31...

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Chapter 31 227 P31.40 (a) εω π ω max == F H G I K J BA B R 1 2 2 ε max max .. . . = = 130 2 0250 400 160 2 T m r a d s V af a f bg (b) θ θθ ππ = zz 22 0 0 2 0 2 d BA d sin (c) The maximum and average would remain unchanged. (d) See Figure 1 at the right. (e) See Figure 2 at the right. Figure 2 Figure 1 t t FIG. P31.40 P31.41 (a) Φ B BA BA t t t = = cos cos . . cos . . cos θω 0 800 0 010 0 2 60 0 8 00 377 m m T m ej (b) =− = d dt t B Φ 302 377 .s i n V a f (c) I R t i n A a f a f (d) P IR t 910 i n W a f (e) Fv τω so τ 241 377 2 i n mN m a f a f t Section 31.6 Eddy Currents P31.42 The current in the magnet creates an upward magnetic field, so the N and S poles on the solenoid core are shown correctly. On the rail in front of the brake, the upward flux of B increases as
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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