902_Physics ProblemsTechnical Physics

902_Physics ProblemsTechnical Physics - 242 P32.6...

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242 Inductance P32.6 From ε = F H G I K J L I t , we have L It == × ∆∆ bg 24 0 10 240 10 3 3 . . V 10.0 A s H. From L N I B = Φ , we have Φ B LI N × =⋅ 400 500 19 2 3 .. . H A Tm 2 ej a f µ . P32.7 L NA × 0 2 0 2 4 4 420 3 00 10 0160 416 10 A a f . . . H =− = = −× × L dI dt dI dt L 175 10 0421 6 V 4.16 10 H As 4 . P32.8 × L dI dt d dt tt 90 0 10 6 32 . e j V (a) At t = 100 s , = 360 mV (b) At t = s , = 180 mV (c) = 90 0 10 2 6 0 3 . af t when t = 300 s . P32.9 (a) Bn I F H G I K J = µµ 00 450 0120 0 040 0 188 . A T (b) Φ B BA × 333 10 8 T m 2 (c) L N I B Φ 0375 m H (d) BL B and are proportional to current; is independent of current Φ P32.10 (a) L × = µπ 0 2 0 2 3 2 120 5 00 10 00900 15 8 A a f . . . H (b) =→ = = × = ΦΦ B m B m L 0 2 5 800 1 58 10 12 6 A m H *P32.11 We can directly find the self inductance of the solenoid: L dI dt += 008 01 8 . . V A 0.12 s L L = 533 10 3 0 2 V
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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