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904_Physics ProblemsTechnical Physics

# 904_Physics ProblemsTechnical Physics - 244 P32.16...

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244 Inductance P32.16 Taking τ = L R , II e t = 0 : dI dt Ie t =− F H G I K J 0 1 IR L dI dt += 0 will be true if IL I e tt 00 1 0 Re −− +− F H G I K J = ττ ej . Because = L R , we have agreement with = . P32.17 (a) == × = L R 200 10 200 3 .. s m s (b) e e t = F H G I K J −= max . . 1 600 10 1 7 6 0250200 e j V 4.00 A (c) I R max . . == = ε 150 V 4.00 A (d) 0 800 1 2 00 0 200 3 22 l n . . . →= = et t ms ms ms af a f FIG. P32.17 P32.18 I R ee t = = 1 120 900 13 0 2 1.80 7 00 e j . . . A ∆∆ VI R VV R LR = = = 3 02 9 00 27 2 120 27 2 92 8 . V V P32.19 Note : It may not be correct to call the voltage or emf across a coil a “potential difference.” Electric potential can only be defined for a conservative electric field, and not for the electric field around an inductor. (a) ∆Ω R R = 8 00 2 00 16 0 . A V and = = 36 0 16 0 20 0 ... V V . Therefore, V V R L 16 0 0800 . . V 20.0 V . (b) R R = 4 50 8 00 36 0 . V = 0 FIG. P32.19 P32.20 After a long time, 12 0 0 200 A = R . Thus, R = 60 0 . . Now, = L R gives ×
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