248 InductanceP32.35(a)ULI==1212400050022..H AafafU=. J(b)When the current is 1.00 A,Kirchhoff’s loop rule reads+−−=22 01 005 000...V Aa fΩ∆VL.Then∆VL=17 0. V.The power being stored in the inductor isIVL∆==100170.A VW.FIG. P32.35(c)P∆220Vaf=11 0. WP32.36From Equation 32.7,IReRt L=−−ε1ej.(a)The maximum current, after a long time t, isIR200A.At that time, the inductor is fully energized and=∆afaf.VW.(b)lostW=IR222 005 0020 0.Ω(c)inductordrop∆0(d)ULI=22210 02 00220 0.AJP32.37We haveuE=∈022anduB=202µ.Therefore∈=0220EBsoBE200=∈2=∈ =××=×−583680 10300 10227 10...VmmsT.P32.38The total magnetic energy is the volume integral of the energy density,uB=202.Because Bchanges with position, uis not constant. For BBRr=FHGIKJ02,uBRr=FHGIKJFHGIKJ02042.Next, we set up an expression for the magnetic energy in a spherical shell of radius
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .