909_Physics ProblemsTechnical Physics

909_Physics ProblemsTechnical Physics - Chapter 32 Section...

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Chapter 32 249 Section 32.4 Mutual Inductance P32.39 It I e t t 1 af = max α ω sin with I max . = 500±A,± = 00250 1 . s , and = 377 rad s dI dt Ie t t t 1 =− + max sin cos αωωω bg . At t = 0800 s , dI dt e 1 00200 5 00 0 025 0 0 800 377 377 0 800 377 + .. s i n . c o s . . As b g ch dI dt 1 3 185 10 A s . Thus, ε 2 1 M dI dt : M dI dt = = + × = 2 1 320 173 . . V 1.85 10 A s mH 3 . P32.40 2 1 44 1 00 10 1 00 10 1 000 × × M dI dt t ..c o s H A s ej e j 2 100 max . = V P32.41 M dI dt == = 2 1 96 0 80 0 . . mV 1.20 A s mH P32.42 Assume the long wire carries current I. Then the magnitude of the magnetic field it generates at distance x from the wire is B I x = µ π 0 2 , and this field passes perpendicularly through the plane of the loop. The flux through the loop is Φ B dB d A B d x I dx x I =⋅= = = = F H G I K J zz z z BA A AA 0 0400 0 22 170 . ln . . mm 1.70 mm . The mutual inductance between the wire and the loop is then
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