916_Physics ProblemsTechnical Physics

916_Physics ProblemsTechnical Physics - 256 Inductance N 0...

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256 Inductance P32.65 (a) At the center, B NI R R R = + = µµ 0 2 22 32 0 20 2 ej . So the coil creates flux through itself Φ B BA R RN I R == ° = cos cos θ µ π 0 2 0 2 0 2 . When the current it carries changes, ε L B N d dt NN R dI dt L dI dt =− ≈− F H G I K J Φ 2 0 so LN R 2 2 0 . (b) 2 3 0 3 r = . m af so r 014 . m L L ≈× = × −− 2 14 1 0 0 1 4 2 81 0 100 27 7 e j TmA m H nH .. ~ (c) L R = ×⋅ 28 10 270 10 10 7 9 . . VsA VA s L R ~1 ns P32.66 (a) If unrolled, the wire forms the diagonal of a 0.100 m (10.0 cm) rectangle as shown. The length of this rectangle is L 980 0100 m m a f . L 0.100 m 9.80 m FIG. P32.66(a) The mean circumference of each turn is Cr = 2 , where ′= + r 24 0 0 644 2 mm is the mean radius of each turn. The number of turns is then: N L C = = = 4 00 6 4 4 21 0 127 3 m m a f . (b)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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