256
Inductance
P32.65
(a)
At the center,
B
NI
R
R
R
=
+
=
µµ
0
2
22
32
0
20
2
ej
.
So the coil creates flux through itself
Φ
B
BA
R
RN
I
R
==
°
=
cos
cos
θ
µ
π
0
2
0
2
0
2
.
When the current it carries changes,
ε
L
B
N
d
dt
NN
R
dI
dt
L
dI
dt
=−
≈−
F
H
G
I
K
J
Φ
2
0
so
LN
R
≈
2
2
0
.
(b)
2
3 0 3
r
=
. m
af
so
r
≈
014
.
m
L
L
≈×
⋅
=
×
−−
2
14 1
0
0
1
4
2
81
0
100
27
7
e
j
TmA
m
H
nH
..
~
(c)
L
R
=
×⋅
=×
−
−
28 10
270
10 10
7
9
.
.
VsA
VA
s
L
R
~1 ns
P32.66
(a)
If unrolled, the wire forms the diagonal of a
0.100 m (10.0 cm) rectangle as shown. The length of
this rectangle is
′
L
980
0100
m
m
a
f
.
′
L
0.100
m
9.80 m
FIG. P32.66(a)
The mean circumference of each turn is
Cr
=
′
2
, where
′=
+
r
24 0 0 644
2
mm is the mean
radius of each turn. The number of turns is then:
N
L
C
=
′
=
−
+×
=
−
4
00
6
4
4
21
0
127
3
m
m
a
f
.
(b)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .
 Fall '11
 Staff
 Physics, Current, Inductance

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