919_Physics ProblemsTechnical Physics

# 919_Physics ProblemsTechnical Physics - Chapter 32 P32.72...

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Chapter 32 259 P32.72 (a) The instant after the switch is closed, the situation is as shown in the circuit diagram of Figure (a). The requested quantities are: II R I R VV V LC R R == = = 0 0 00 ,, εε ∆∆ (b) After the switch has been closed a long time, the steady-state conditions shown in Figure (b) will exist. The currents and voltages are: III V LCR R === = 000 0 ε + + I L = 0 V L = 0 I R = 0 V R = 0 Q = 0 C V C = 0 0 Figure (b) + + I L = 0 V L = 0 V R = Q =0 V C = 0 0 Figure (a) 0 I R = 0 /R I C = 0 /R FIG. P32.72 P32.73 When the switch is closed, as shown in figure (a), the current in the inductor is I : 12 0 7 50 10 0 0 0 267 .. . . −− = = A. When the switch is opened, the initial current in the inductor remains at 0.267 A. IR V =∆ :0 2 6 7 8 0 0 A V af R R 300 (a) (b) FIG. P32.73 P32.74 (a) L NA 1 01 2 1 7 2 4 4 4 10 1 000 1 00 10 0500 251 10 251 ×⋅ × = µ
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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