927_Physics ProblemsTechnical Physics

927_Physics ProblemsTechnical Physics - 268 P33.4...

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268 Alternating Current Circuits P33.4 (a) ∆∆ vV t R = max sin ω R = 0250 . max bg , so sin . t = 0250, or t = sin . 1 af . The smallest angle for which this is true is t = 0253 . rad Thus, if t = 00100 . s , == 25 3 . . rad 0.010 0 s rad s . (b) The second time when R = . max , t = sin . 1 again. For this occurrence, ωπ t =− = 289 .. rad rad (to understand why this is true, recall the identity sin sin πθ θ −= from trigonometry). Thus, t 0114 . . rad 25.3 rad s s. P33.5 iI t R = max sin becomes 0 600 0 007 00 .s i n . = . Thus, 0 007 00 0 600 0 644 1 i n . . and 91 9 2 r ads f so f = 14 6 . H z. P33.6 P = IV rms rms and V rms V = 120 for each bulb (parallel circuit), so: II V 12 1 150 125 = = rms W 120 V A . , and R V I R 1 1 2 120 96 0 === = rms V 1.25 A . I V 3 3 100 0833 = rms W 120 V A . , and R V I 3 3 120 144 = rms V 0.833 A . P33.7 V max . = 15 0 V and
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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