268 Alternating Current CircuitsP33.4(a)∆∆vVtR=maxsinωR=0250.maxbg, so sin.t=0250, or t=−sin.1af.The smallest angle for which this is true is t=0253.rad Thus, if t=00100. s,==25 3..rad0.010 0 srad s .(b)The second time when R=.max, t=−sin.1again. For this occurrence,ωπt=−=289..radrad (to understand why this is true, recall the identitysinsinπθθ−=from trigonometry). Thus,t0114..rad25.3 rad ss.P33.5iItR=maxsinbecomes0 6000 007 00.sin.=.Thus,0 007 000 6000 6441in..−and 91 92radsfsof=14 6. Hz.P33.6P=IVrmsrms∆and ∆VrmsV=120for each bulb (parallel circuit), so:IIV121150125==∆rmsW120 VA., and RVIR11212096 0====∆ΩrmsV1.25 A.IV331000833=∆rmsW120 VA., and RVI33120144=∆ΩrmsV0.833 A.P33.7∆Vmax.=15 0 V and
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .