933_Physics ProblemsTechnical Physics

933_Physics ProblemsTechnical Physics - 274 P33.32...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
274 Alternating Current Circuits P33.32 ZR XX LC =+ 2 2 bg or −= 22 R I V Z VI = = F H G I K J = F H G I K J == = ° = −− af a fa f a f 75 0 45 0 60 0 60 0 53 1 210 280 210 2 80 53 1 353 11 ... tan tan . . . cos . cos . 45.0 V 75.0 A V A W rms rms rms rms ΩΩΩ φ P P33.33 (a) ° = × IV rms rms W a f cos . cos . . 9 00 180 37 0 1 29 10 3 = IR rms 2 so 1 29 10 9 00 3 2 .. ×= a f R and R = 16 0 . . (b) tan = R becomes tan . −° = 37 0 16 a f :s o 12 0 . P33.34 XL L = ωπ 2 600 00250 942 . s H b g = + = 2 2 20 0 9 42 22 1 . ΩΩ (a) I V Z rms rms V 22.1 A = 120 543 . (b) = F H G I K J tan . . . 1 20 0 25 2 so power factor cos . 0905 . (c) We require = 0 . Thus, = : 1 26 0 0 1 . . s Ω= π ej C and C = 281 F µ . (d) PP bd = or V R bb b d rms rms rms b g cos = 2 ∆∆ VR V I db b b rms rms rms A V b g a f a f = cos . . . 20 0 120 5 43 0 905 109 P33.35 Consider a two-wire transmission line: I V rms rms = and power loss
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online