936_Physics ProblemsTechnical Physics

936_Physics - Chapter 33 P33.43 1 For the circuit of Problem 22 0 = 1 = = 251 rad s e160 10 Hje99.0 10 Fj L b 251 rad sge160 10 H j = = 0.591 Q= LC

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Chapter 33 277 P33.43 For the circuit of Problem 22, ω 0 36 11 160 10 99 0 10 251 == ×× = −− LC H F rad s ej . Q L R × = 0 3 251 160 10 68 0 0591 rad s H bg . . . For the circuit of Problem 23, Q L R L RL C R L C = = × × = 0 3 6 150 460 10 10 0987 H 21.0 F .. The circuit of Problem 23 has a sharper resonance. Section 33.8 The Transformer and Power Transmission P33.44 (a) V 2 1 13 120 9 23 , rms V V af . (b) ∆∆ VI 22 ,, rms rms rms rms = 120 0 350 9 23 2 A V , rms a fa f a f = I I 2 42 0 455 , . . rms W 9.23 V A for a transformer with no energy loss. (c) P = 42 0 . W from part (b). P33.45 V N N V out in V b g a f max max F H G I K J = 2 1 2000 350 170 971 V out
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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