942_Physics ProblemsTechnical Physics

# 942_Physics ProblemsTechnical Physics - Chapter 33 283...

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Chapter 33 283 (only the positive root is physical.) Now equation (3) gives X C C = = 2 131 10 99 6 106 7 1 4 2 12 .. . af ΩΩ ω (only the positive root is physical.) CX C C == = × = bg b g 1 1 5 377 106 7 2 49 10 s F . Now equation (1) gives XX XL L X L LC L L −= ± ×− = ± =+= = = 1 194 10 99 6 44 99 106 7 44 99 61 74 0164 4 2 . . . or 151.7 H or 0.402 H ΩΩΩ P33.59 The resistance of the circuit is R V I = 12 0 19 0 . . V 0.630 A . The impedance of the circuit is Z V I = rms rms V 0.570 A 24 0 42 1 . ZR L LZ R 222 2 22 11 377 42 1 19 0 99 6 =+ =− = . mH *P33.60 The lowest-frequency standing-wave state is NAN. The distance between the clamps we represent as Ld NN λ 2 . The speed of transverse waves on the string is vf T fL == = µ 2 . The magnetic force on the wire oscillates at 60 Hz, so the wire will oscillate in resonance at 60 Hz. T L 0019 60 4 2 2 . k g m s = bg TL = 274 2 kg ms 2 ej Any values of T and L related according to this expression will work, including if m N LT 0200
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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