945_Physics ProblemsTechnical Physics

945_Physics ProblemsTechnical Physics - 286 Alternating...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
286 Alternating Current Circuits P33.67 (a) From Equation 33.41, N N V V 1 2 1 2 = . Let input impedance Z V I 1 1 1 = and the output impedance Z V I 2 2 2 = so that N N ZI 1 2 11 22 = . But from Eq. 33.42, I I V V N N 1 2 2 1 2 1 == . So, combining with the previous result we have N N Z Z 1 2 1 2 = . (b) N N Z Z 1 2 1 2 8000 800 31 6 = . . P33.68 PI R V Z R F H G I K J rms 2 rms 2 , so 250 120 40 0 2 2 W V = af Z . : ZR L C =+− F H G I K J 2 2 1 ω 250 120 40 0 40 0 2 0 185 1 2 65 0 10 2 2 6 2 = +−× a f a f ej . .. . ππ ff and 250 576 000 1 600 1 162 4 2 448 5 2 2 = +− f 1 2304 1 600 1 3511 5 692 3 5 995 300 2 24 2 = + f fff so 1 3511 6 396 3 5 995 300 0 42 −+= f 2 2 6 396 3 6 396 3 4 1 3511 5 995 300 213511 34465 12874 = ±− = . . bg b
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online