959_Physics ProblemsTechnical Physics

959_Physics ProblemsTechnical Physics - 300 Electromagnetic...

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300 Electromagnetic Waves Section 34.4 Momentum and Radiation Pressure P34.26 The pressure P upon the mirror is P S c = 2 av where A is the cross-sectional area of the beam and S A av = P . The force on the mirror is then FP A cA A c == F H G I K J = 22 PP . Therefore, F = × × 2100 10 31 0 667 10 3 8 10 ej . N . P34.27 For complete absorption, P S c × = 25 0 300 10 83 3 8 . . . nP a . P34.28 (a) The radiation pressure is 21340 893 10 8 6 ±Wm ±ms Nm 2 2 2 . . × . Multiplying by the total area, A 600 10 5 m 2 gives: F = 536 N . (b) The acceleration is: a F m = × 4 . . N 6000 kg ms 2 . (c) It will arrive at time
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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