300 Electromagnetic WavesSection 34.4Momentum and Radiation PressureP34.26The pressure Pupon the mirror isPSc=2avwhere Ais the cross-sectional area of the beam andSAav=P.The force on the mirror is thenFPAcAAc==FHGIKJ=22PP.Therefore,F=××=×−−2100 10310667 103810ej. N.P34.27For complete absorption, PSc×=25 0300 1083 38... nPa .P34.28(a)The radiation pressure is21340893 1086±Wm±msNm222..×−.Multiplying by the total area, A600 105m2gives:F=536N.(b)The acceleration is:aFm=×−4..N6000 kgms2.(c)It will arrive at time
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .