963_Physics ProblemsTechnical Physics

# 963_Physics ProblemsTechnical Physics - 304 Electromagnetic...

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Unformatted text preview: 304 Electromagnetic Waves Section 34.6 P34.38 The Spectrum of Electromagnetic Waves From the electromagnetic spectrum chart and accompanying text discussion, the following identifications are made: Frequency, f 2 Hz = 2 × 10 0 Hz 2 kHz = 2 × 10 3 Hz 2 MHz = 2 × 10 6 Hz 2 GHz = 2 × 10 9 Hz 2 THz = 2 × 10 12 Hz 2 PHz = 2 × 10 15 Hz 2 EHz = 2 × 10 18 Hz 2 ZHz = 2 × 10 21 Hz 2 YHz = 2 × 10 24 Hz 2 km = 2 × 10 3 m 2 m = 2 × 10 0 m 2 mm = 2 × 10 −3 m 2 µm = 2 × 10 −6 m 2 nm = 2 × 10 −9 m 2 pm = 2 × 10 −12 m 2 fm = 2 × 10 −15 m 2 am = 2 × 10 −18 m P34.40 Frequency, f = 1.5 × 10 5 Hz 1.5 × 10 8 Hz 1.5 × 10 11 Hz 1.5 × 10 14 Hz 1.5 × 10 17 Hz 1.5 × 10 20 Hz 1.5 × 10 23 Hz 1.5 × 10 26 Hz f= (a) (b) c λ = 3.00 × 10 8 m s 5.50 × 10 −7 m f= c λ = Classification Radio Radio Radio Microwave Infrared Ultraviolet X-ray Gamma ray Gamma ray c λ Classification Radio Radio Microwave Infrared Ultraviolet/X-ray X-ray/Gamma ray Gamma ray Gamma ray = 5.45 × 10 14 Hz 3 × 10 8 m s ~ 10 8 Hz 1.7 m radio wave 1 000 pages, 500 sheets, is about 3 cm thick so one sheet is about 6 × 10 −5 m thick. f= P34.41 c f 150 Mm 150 km 150 m 15 cm 150 µm 150 nm 150 pm 150 fm 150 am Wavelength, λ P34.39 Wavelength, λ = 3.00 × 10 8 m s 6 × 10 −5 m ~ 10 13 Hz infrared (a) fλ = c gives e5.00 × 10 19 (b) fλ = c gives e4.00 × 10 9 j λ = 6.00 × 10 −12 m = 6.00 pm j λ = 0.075 m = 7.50 cm Hz λ = 3.00 × 10 8 m s : Hz λ = 3.00 × 10 8 m s : ...
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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