969_Physics ProblemsTechnical Physics

969_Physics ProblemsTechnical Physics - 310 Electromagnetic...

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310 Electromagnetic Waves P34.61 (a) λ == × × = c f 300 10 20 0 10 150 8 91 . . . ms s cm (b) Ut × × = × = −− P af ej e j 25 0 10 1 00 10 25 0 10 25 0 39 6 .. . . Js s J J µ FIG. P34.61 (c) u U V U r U rct av J 0.060 0 m m s s = = × ×× ππ π 22 6 2 89 25 0 10 3 00 10 1 00 10 ejej a f bg e j A . u av 33 Jm m = 737 10 737 3 (d) E u max . . = = × ×⋅ = 2 2 7 37 10 885 10 408 10 408 0 3 12 4 av 3 ±Jm CNm ±Vm ±kVm B E c max max . . . × × = 136 10 136 4 8 4 Vm T T (e) FP A S c AuA F H G I K J ==× = × = av 3 m N N 00600 833 10 833 3 2 5 . . πµ P34.62 (a) On the right side of the equation, Cm s CNm m s Nm C m s Csm Nm s J s W 22 23 24 3 2 3 = ⋅⋅⋅⋅ ⋅⋅ = . (b) Fm aq E or a qE m × × 160 10 100 911 10 176 10 19 31 13 . . . C N C kg 2 . The radiated power is then: = = qa c 0 3 19 2 13 2 12 8 3 27 6 1 60 10 1 76 10 6 8 85 10 3 00 10 175 10 . e j e j W. (c) a m v r qvB c F H G I K J = 2 so v qBr m = . The proton accelerates at a v r qBr m = × × 2 2 19 2 2 27 2 14 1 60 10 0 350 0 500 167 10
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