326 The Nature of Light and the Laws of Geometric OpticsP35.26Refraction proceeds according to1 001 6612.sin.sinafθθ=.(1)(a)For the normal component of velocity to be constant,vv1122coscos=orcca fcos.cos166=FHGIKJ.(2)We multiply Equations (1) and (2), obtaining:sincossincos=orsinsin=.The solution 0==does not satisfy Equation (2) and must be rejected. The physicalsolution is 2180 2=°−or 2190 0−.. Then Equation (1) becomes:sin.cos=, or tan.θ1=which yields158 9..(b)Light entering the glass slows down and makes a smaller angle with the normal. Both effectsreduce the velocity component parallel to the surface of the glass, so that component cannotremain constant, or will remain constant only in the trivial case 0.P35.27See the sketch showing the path of the
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