{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

985_Physics ProblemsTechnical Physics

985_Physics ProblemsTechnical Physics - 326 The Nature of...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
326 The Nature of Light and the Laws of Geometric Optics P35.26 Refraction proceeds according to 1 00 1 66 1 2 . sin . sin a f a f θ θ = . (1) (a) For the normal component of velocity to be constant, v v 1 1 2 2 cos cos θ θ = or c c a f cos . cos θ θ 1 2 1 66 = F H G I K J . (2) We multiply Equations (1) and (2), obtaining: sin cos sin cos θ θ θ θ 1 1 2 2 = or sin sin 2 2 1 2 θ θ = . The solution θ θ 1 2 0 = = does not satisfy Equation (2) and must be rejected. The physical solution is 2 180 2 1 2 θ θ = °− or θ θ 2 1 90 0 = °− . . Then Equation (1) becomes: sin . cos θ θ 1 1 1 66 = , or tan . θ 1 1 66 = which yields θ 1 58 9 = ° . . (b) Light entering the glass slows down and makes a smaller angle with the normal. Both effects reduce the velocity component parallel to the surface of the glass, so that component cannot remain constant, or will remain constant only in the trivial case
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern