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989_Physics ProblemsTechnical Physics

# 989_Physics ProblemsTechnical Physics - 330 The Nature of...

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330 The Nature of Light and the Laws of Geometric Optics P35.37 sin θ c n n = 2 1 : θ c n n = F H G I K J sin 1 2 1 (a) Diamond: θ c = F H G I K J = ° sin . . . 1 1 333 2 419 33 4 (b) Flint glass: θ c = F H G I K J = ° sin . . . 1 1 333 1 66 53 4 (c) Ice: Since n n 2 1 > , there is no critical angle . P35.38 sin . . . θ c n n = = = air pipe 1 00 1 36 0 735 θ c = ° 47 3 . Geometry shows that the angle of refraction at the end is φ θ = °− = °− °= ° 90 0 90 0 47 3 42 7 . . . . c . Then, Snell’s law at the end, 1 00 1 36 42 7 . sin . sin . θ = ° gives θ = ° 67 2 . . The 2- µ m diameter is unnecessary information. FIG. P35.38 P35.39 sin θ c n n = 2 1 n n 2 1 88 8 1 000 3 0 999 8 1 000 08 = °= = sin . . . . b gb g FIG. P35.39 *P35.40 (a) A ray along the inner edge will escape if any ray escapes. Its angle of incidence is described by sin θ = R d R and by n sin sin θ > ° 1 90 . Then n R d R > a f 1 nR nd R > nR R nd
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