989_Physics ProblemsTechnical Physics

989_Physics ProblemsTechnical Physics - 330 The Nature of...

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330 The Nature of Light and the Laws of Geometric Optics P35.37 sin θ c n n = 2 1 : c n n = F H G I K J sin 1 2 1 (a) Diamond: c = F H G I K J sin . . . 1 1333 2419 33 4 (b) Flint glass: c = F H G I K J sin . . . 1 166 53 4 (c) Ice: Since nn 21 > , there is no critical angle . P35.38 sin . . . c n n == = air pipe 100 136 0735 c 47 3 . Geometry shows that the angle of refraction at the end is φθ ° 90 0 90 0 47 3 42 7 .. . . c . Then, Snell’s law at the end, 1 00 1 36 42 7 . sin . sin . gives 67 2 . . The 2- µ m diameter is unnecessary information. FIG. P35.38 P35.39 sin c n n = 2 1 88 8 1 000 3 0 999 8 1 000 08 = = sin . . . . bg FIG. P35.39 *P35.40 (a) A ray along the inner edge will escape if any ray escapes. Its angle of incidence is described by sin = Rd R and by n sin sin 1 90 . Then nR d R > a f 1 nR nd R −> nR R nd R nd n > 1 . (b) As d 0, R min 0 . This is reasonable.
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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