340 The Nature of Light and the Laws of Geometric OpticsP35.66Observe in the sketch that the angle of incidence at point Pis γ, andusing triangle OPQ:sin=LR.Also,cossinγγ=−=−1222RLR.Applying Snell’s law at point P, 100.sinsinφ=n.Thus,sinsin==nLnRandcossinφφ=−122nRLnR.FIG. P35.66From triangle OPS, φα++ °+ °−= °90 090 0180..afbgor the angle of incidence at point Sis αγφ.Then, applying Snell’s law at point Sgives100.sinsinsinθα==−nnorsinsin coscos sinθγ=FHGIKJ−−−FHGIKJLNMMOQPPLRLnRRLnR222sinθ−−FHIKLRLRL2222and−−FHIKLNMOQP−sin12222LRLRL.P35.67As shown in the sketch, the angle of incidence at point Ais:=FHGIKJ=FHGIKJ=°−−sinsin..11230 0dRm2.00 m.If the emerging ray is to be parallel to the incident ray, the path
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .