999_Physics ProblemsTechnical Physics

999_Physics ProblemsTechnical Physics - 340 P35.66 The...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
340 The Nature of Light and the Laws of Geometric Optics P35.66 Observe in the sketch that the angle of incidence at point P is γ , and using triangle OPQ : sin = L R . Also, cos sin γγ =− = 1 2 22 RL R . Applying Snell’s law at point P , 100 .s i n s i n φ = n . Thus, sin sin == n L nR and cos sin φφ = 1 2 2 nR L nR . FIG. P35.66 From triangle OPS , φα ++ ° + ° −= ° 90 0 90 0 180 .. a f bg or the angle of incidence at point S is αγφ . Then, applying Snell’s law at point S gives 100 . sin sin sin θα ==− nn or sin sin cos cos sin θγ = F H G I K J F H G I K J L N M M O Q P P L R L nR R L nR 2 2 2 sin θ F H I K L R L R L 2 2 2 2 and F H I K L N M O Q P sin 1 2 2 2 2 L R L R L . P35.67 As shown in the sketch, the angle of incidence at point A is: = F H G I K J = F H G I K J −− sin sin . . 11 2 30 0 d R m 2.00 m . If the emerging ray is to be parallel to the incident ray, the path
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online