1015_Physics ProblemsTechnical Physics

1015_Physics ProblemsTechnical Physics - 356 * P36.15 Image...

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356 Image Formation *P36.15 M q p =− qM p pq f R R R +== + = = 001330 039 111 2 1 30 1 2 2 253 0790 1 .. . . . cm cm cm cm m cm af FIG. P36.15 The cornea is convex, with radius of curvature . c m . *P36.16 With M h h q p = = + =+ 400 0400 . . cm 10.0 cm qp . the image must be virtual. (a) It is a convex mirror that produces a diminished upright virtual image. (b) We must have pq += 42 0 cm 42 0 pp 42 0 0 400 cm p == 42 0 30 0 . . cm 1.40 cm The mirror is at the 30.0 cm mark . (c) 111 1 30 1 0430 1 00500 pq f f + cm cm cm . . f 20 0 The ray diagram looks like Figure 36.15(c) in the text. P36.17 (a) 500 m bg
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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