Chapter 36
357
P36.18
Assume that the object distance is the same in both cases (i.e., her face is the same distance from the
hubcap regardless of which way it is turned). Also realize that the near image (
q
=−
10 0
.
cm ) occurs
when using the convex side of the hubcap. Applying the mirror equation to both cases gives:
(concave side:
RR
=
,
q
30 0
cm )
11
30 0
2
pR
−=
.
or
2
30 0
30 0
R
p
p
=
−
.
.
cm
cm
af
(1)
(convex side:
,
q
10 0
10 0
2
−
.
or
2
10 0
10 0
R
p
p
=
−
.
.
cm
cm
.
(2)
(a)
Equating Equations (1) and (2) gives:
30 0
300
10 0
.
.
.
cm
cm
−
p
p
or
p
=
15 0
cm .
Thus, her face is
15 0
cm from the hubcap.
(b)
Using the above result (
p
=
15 0
cm ) in Equation (1) gives:
23
0
0
1
5
0
15 0
R
=
−
..
.
cm
cm
30.0 cm
cm
or
21
30 0
R
=
cm
and
R
=
60 0
.
The radius of the hubcap is
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .
 Fall '11
 Staff
 Physics

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