1016_Physics ProblemsTechnical Physics

1016_Physics ProblemsTechnical Physics - Chapter 36 P36.18...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 36 357 P36.18 Assume that the object distance is the same in both cases (i.e., her face is the same distance from the hubcap regardless of which way it is turned). Also realize that the near image ( q =− 10 0 . cm ) occurs when using the convex side of the hubcap. Applying the mirror equation to both cases gives: (concave side: RR = , q 30 0 cm ) 11 30 0 2 pR −= . or 2 30 0 30 0 R p p = . . cm cm af (1) (convex side: , q 10 0 10 0 2 . or 2 10 0 10 0 R p p = . . cm cm . (2) (a) Equating Equations (1) and (2) gives: 30 0 300 10 0 . . . cm cm p p or p = 15 0 cm . Thus, her face is 15 0 cm from the hubcap. (b) Using the above result ( p = 15 0 cm ) in Equation (1) gives: 23 0 0 1 5 0 15 0 R = .. . cm cm 30.0 cm cm or 21 30 0 R = cm and R = 60 0 . The radius of the hubcap is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online