1018_Physics ProblemsTechnical Physics

# 1018_Physics ProblemsTechnical Physics - Chapter 36 P36.22...

This preview shows page 1. Sign up to view the full content.

Chapter 36 359 P36.22 When R → ∞ , the equation describing image formation at a single refracting surface becomes q p n n = − F H G I K J 2 1 . We use this to locate the final images of the two surfaces of the glass plate. First, find the image the glass forms of the bottom of the plate. q B 1 1 33 1 66 8 00 6 41 = − F H G I K J = − . . . . cm cm a f This virtual image is 6.41 cm below the top surface of the glass of 18.41 cm below the water surface. Next, use this image as an object and locate the image the water forms of the bottom of the plate. q B 2 1 00 1 33 18 41 13 84 = − F H G I K J = − . . . . cm cm a f or 13.84 cm below the water surface. Now find image the water forms of the top surface of the glass. q 3 1 1 33 12 0 9 02 = − F H G I K J = − . . . cm cm a f or 9.02 cm below the water surface. Therefore, the apparent thickness of the glass is t = = 13 84 9 02 4 82 . . . cm cm cm . P36.23 From Equation 36.8 n p n q n n R 1 2 2 1 + = . Solve for q to find q n Rp p n n n R = 2 2 1 1 b g . In this case, n 1 1 50 = . , n 2 1 00 = . , R = − 15 0 . cm and p = 10 0 . cm . So q = = −
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern