Chapter 36359P36.22When R→∞, the equation describing image formation at a single refracting surface becomesqpnn=−FHGIKJ21. We use this to locate the final images of the two surfaces of the glass plate. First, findthe image the glass forms of the bottomof the plate.qB1133166800641FHGIKJ....cmcmafThis virtual image is 6.41 cm below the top surface of the glass of 18.41 cm below the water surface.Next, use this image as an object and locate the image the water forms of the bottom of the plate.qB210018 4113 84FHGIKJ..cmcmafor13.84 cm below the water surface.Now find image the water forms of the topsurface of the glass.q3112 09 02FHGIKJ.cmcmafor9.02 cm below the water surface.Therefore, the apparent thickness of the glass is ∆t=13 849 024 82.cmcmcm .P36.23From Equation 36.8npnqnnR1221+=−.Solve for qto findqnRppnn=−−2211bg.In this case,n1150=.,n2=R15 0. cmandp=10 0cm .Soq=−−10 01 00 1 501 5015 0857
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .